From: shallit@graceland.uwaterloo.ca (Jeffrey Shallit) Subject: Re: pairwise relatively prime numbers in an interval Date: 18 Aug 2000 15:42:03 GMT Newsgroups: sci.math.research Summary: [missing] In article , Edwin Clark wrote: > >Sorry, but I goofed in stating the question. This >is what I meant to ask: > >For integers x > 0 and y >=0, let F(x,y) denote the maximum cardinality >of a subset of { y+1, y+2, . . . ,y + x } whose elements are pairwise >relatively prime, and let > > F*(x) = min { F(x,y) | y >=0 }. > >In 1971 Erdos and Selfridge proved that for >every e > 0, if x is sufficiently large then > > x^{1/2 - e} < F*(x). > >Can anyone tell me more about lower bounds for F*(x)? > >Thanks, > >Edwin Clark > >------------------------------------------------------ > W. Edwin Clark >Department of Mathematics, University of South Florida, >4202 East Fowler Avenue, PHY 114, Tampa, FL 33620-5700 > http://www.math.usf.edu/~eclark/ >------------------------------------------------------ I've already responded to Edwin Clark by e-mail, but here goes again: In a paper I wrote with my student Ming-wei Wang, and recently presented at a conference in London, Ontario, we observe the following: Let f(r) denote the least integer y such that every interval of y consecutive integers contains at least r pairwise relatively prime integers. Let C(r) be the classical Jacobsthal function, i.e., C(r) counts the maximum distance between two consecutive numbers relatively prime to n, where n is divisible by r distinct primes. Then f(r) = C(r-1) for r >= 1. Iwaniec proved the upper bound C(r) = O(r^2 (log r)^2) in 1978, and no one has improved this bound since then. The general consensus seems that it is probably quite hard to improve. Since any improvement on C would give a corresponding improvement on f, and vice versa, we may conclude that f(r) = O(r^2 (log r)^2) and that no one currently knows anything better for an upper bound. There are some lower bounds known for C(r), but since I am away from my papers and books I cannot find them at the moment. I believe it is known that C(r) > r * t(r), where t is something roughly on the order of (log r)/(log log r), but I am probably misremembering the exact bound. Jeffrey Shallit, Computer Science, University of Waterloo, Waterloo, Ontario N2L 3G1 Canada shallit@graceland.uwaterloo.ca URL = http://www.math.uwaterloo.ca/~shallit/