From: David desJardins Subject: Re: 2, 1729, ? Date: 01 Jan 2001 19:15:01 -0800 Newsgroups: sci.math.research Summary: Smallest numbers representables as sums of 2 cubes in k ways. Edwin Clark writes: > Clearly R(0) = 2. From the Hardy-Ramanujan story we know > R(1) = 1729. Typing 2,1729 at http://www.research.att.com/~njas/sequences/ is the easiest way to start with questions like this one. Your sequence is number A011541, the "Hardy-Ramanujan numbers". > A. Is R(k) defined for all k? Apparently so. > B. What is R(2)? 87539319. > C. What about R(k) for other values of k? R(3)=6963472309248. R(4)=48988659276962496. R(5)<=8230545258248091551205888. > D. Is the answer the same if we say "k+1 distinct solutions" > instead of "more than k distinct solutions. Probably. David desJardins ============================================================================== From: Werner Nickel Subject: Re: 2, 1729, ? Date: 2 Jan 2001 13:04:10 GMT Newsgroups: sci.math.research Edwin Clark wrote: > Let k be a positive integer. > Let R(k) be the smallest positive integer n for which > n = x^3 + y^3 > has more than k distinct soluions x,y in positive integers? [...] > B. What is R(2)? A straight forward exhaustive search in GAP 4 revealed R(2) = 87,539,319 and that R(3) <> 87,539,319. The three solutions are: [ 414, 255 ], [ 423, 228 ], [ 436, 167 ] Other values for n with k=2 are: 119,824,488: [ 428, 346 ], [ 492, 90 ], [ 493, 11 ] 143,604,279: [ 423, 408 ], [ 460, 359 ], [ 522, 111 ] 175,959,000: [ 525, 315 ], [ 552, 198 ], [ 560, 70 ] All the best, Werner Nickel ============================================================================== From: njas@research.att.com (N. J. A. Sloane) Subject: Re: 2, 1729, ? Date: 2 Jan 01 14:01:04 GMT Newsgroups: sci.math.numberthy The EIS contains this sequence: %I A011541 %S A011541 2,1729,87539319,6963472309248,48988659276962496 %N A011541 Taxi-cab or Hardy-Ramanujan numbers: the smallest number that is the sum of 2 cubes in n ways (an infinite sequence). %D A011541 R. K. Guy, Unsolved Problems in Number Theory, D1. %D A011541 D. Wells, The Penguin Dictionary of Curious and Interesting Numbers. Penguin Books, NY, 1986, 165 and 189. %H A011541 D. W. Wilson, The Fifth Taxicab Number is 48988659276962496,J. Integer Sequences, Vol. 2, 1999, #9. %H A011541 5th term computed independently (and slightly later) by D. J. Bernstein %H A011541 Link to a section of Eric Weisstein's World of Mathematics. %H A011541 Link to a section of Eric Weisstein's World of Mathematics. %Y A011541 Cf. A023050, A003826, A001235. %K A011541 nonn,nice,hard %O A011541 1,1 %A A011541 njas, Robert G. Wilson v (rgwv@kspaint.com) %E A011541 dww reports a(6) <= 8230545258248091551205888. NJAS ============================================================================== From: Henayni@hotmail.com (Matt Herman) Subject: Re: 2, 1729, ? Date: 2 Jan 01 14:01:04 GMT Newsgroups: sci.math.numberthy Hi, From - Taxicabs and Sums of Two Cubes J. Silverman American Mathematical Monthly, Volume 100, Issue 4 (Apr., 1993), 331-340. - we have the following results. R(2) = 87539319 = 436^3 + 167^3 = 423^3 + 228^3 = 414^3 + 255^3 If you want R(2) to be cube free, the smallest representation is 15170835645 = 517^3 + 2468^3 = 709^3 + 2456^3 = 1733^3 + 2152^3. For the minimal integer with four representations, we have 26059452841000 = 29620^3 + 4170^3 = 28810^3 + 12900^3 = 28423^3 + 14577^3 = 24940^3 + 21930^3. However, as of 1993, there is no known cube-free integer that has four different representations (even when negative x,y are allowed). The main result of the paper is a answer to A. Given any integer N, there exists a positive integer A for which the equation X^3 + Y^3 = A has at least N solutions in integers. From this, it can be easily proven that there are infinitely many positive integer solutions. The method of proof is somewhat constructive -- start with a rational solution to X^3 + Y^3 = 7, P = (2, -1). Then, we have a result that the sequence P, 2P, .. , which never repeats. So take the first N. Then nP has the form (a_n/d_n, b_n/d_n). So multiply the original equation by the product of the d_i (i=1,..n) = B. Then the equation X^3 + Y^3 = 7B^3 has at least N solutions in integers, namely B*(a_n/d_n, b_n,d_n), 0 0 such that for infinitely many positive integeres A, the number of positive integer solutions to the equation X^3 + Y^3 = A exceeds c * (log A)^(1/3). I hope this helps. You could probably get this paper on JSTOR. Happy New Year! ----- Original Message ----- [deleted --djr] ============================================================================== From: kohmoto@z2.zzz.or.jp (y.kohmoto) Subject: a generalized taxi cab Date: 19 Jan 01 13:02:45 GMT Newsgroups: sci.math.numberthy T(k,m,n) : the smallest number such that representable as a sum of m k powers in n ways. ex. T(3,2,n) is the same thing as Ta(n) which is known as Taxi cab Number : the smallest number representable as a sum of two cubes in n ways. for n<=5 , they are known. [The smallest records for T(3,m,n)] T(3,2,6)=Ta(6)<=8230545258248091551205888 = 11239317^3 + 201891435^3 = 17781264^3 + 201857064^3 = 63273192^3 + 199810080^3 = 85970916^3 + 196567548^3 = 125436328^3 + 184269296^3 = 159363450^3 + 161127942^3 . ( David W. Wilson ) I have two examples. T(3,3,16)<=810000^3 = 809730^3+80991^3+9^3 = 807840^3+161856^3+144^3 = 802710^3+242271^3+729^3 = 792720^3+321696^3+2304^3 = 776250^3+399375^3+5625^3 = 766200^3+433800^3+6000^3 = 751680^3+474336^3+11664^3 = 656400^3+628800^3+14400^3 = 796500^3+295500^3+69000^3 = 795000^3+306000^3+69000^3 = 720000^3+540000^3+90000^3 = 782550^3+373725^3+27675^3 = 788355^3+346140^3+15165^3 = 783000^3+371250^3+60750^3 = 724140^3+532980^3+68040^3 = 736306^3+509492^3+6366^3 T(3,4,15)<=1350000^3 = 1349538^3+136140^3+12360^3+462^3 = 1346888^3+256987^3+15397^3+728^3 = 1346737^3+261085^3+7421^3+221^3 = 1339010^3+390610^3+13034^3+466^3 = 1333215^3+449190^3+12330^3+225^3 = 1285830^3+694124-3+12772^3+762^3 = 1349200^3+163440^3+17640^3+1880^3 = 1346760^3+260280^3+34020^3+540^3 = 1342800^3+339570^3+11070^3+540^3 = 1339160^3+388750^3+34930^3+1880^3 = 1337000^3+412880^3+22660^3+1180^3 = 1330500^3+471870^3+25440^3+1170^3 = 1311240^3+590490^3+14310^3+960^3 = 1235150^3+832050^3+11400^3+1000^3 = 1230230^3+842700^3+29680^3+2010^3 In addition: 5949503719112230284735150781047420975571215969633783660978692570826281101309 189803771999166533150006397466555165181072458877^3 +693167423530203568796466556841646172413753795462810020862370805265266981207 049609344143725917800499174450944129560853125400625152^3 -129576938056899065227232353532280140679420086701403228248146670988068053133 80604081166444397018867983934899325^3 =2^1284 2^1284 is 2-adically small, so this is almost an example of a^3+b^3-c^3=0