From: Robin Chapman Subject: RE: Algebraically Closed Field Extensions Date: Sat, 16 Jun 2001 14:14:10 -0400 Newsgroups: sci.math Summary: Fields of finite index in their algebraic closure >===== Original Message From AndrEs Eduardo Caicedo ===== >It is relatively well known that if K is a field of characteristic 0 and >L is an algebraic extension of K such that > 1<[L:K]and L is algebraically closed, then > [L:K]=2, > L=K(square root of -1), and > K is a real-closed field. > >Is it possible to have char K different from 0 and 1<[L:K]with L algebraically closed? No. See e.g., Lang's Algebra. ------------------------------------------------------------ Robin Chapman, www.maths.ex.ac.uk/~rjc/rjc.html "His mind has been corrupted by colours, sounds and shapes." The League of Gentlemen