From: instanton@mail.ru Subject: Re: Commutators in GL_n(R) [Was: Commutators in GL_n(K)] Date: Sun, 11 Feb 2001 12:01:09 GMT Newsgroups: sci.math Summary: Algebraic K-theory of rings (commutators of unions of matrix rings) In article <96428k$kar$1@news1.math.niu.edu>, rusin@vesuvius.math.niu.edu (Dave Rusin) wrote: > In article <963p42$7na$1@wisteria.csv.warwick.ac.uk>, > wrote: > >In article <3A8416A9.5F25C3D0@jps.net>, > > alperin@jps.net writes: > >>Questions of this kind are considered in a recent preprint by U. Rehmann > >>and N. Gordeeva, available from the preprint server at Bielefeld > >>University, Germany. > >> > >>Roger Alperin > > > >I just looked this up. > > What's this? Actual scholarly activity in sci.math? Begone, impostor! > > >In fact the answer to the original question, of > >whether every element of SL_n(K) is a commutator in GL_n(K) is yes, except > >when n=|K|=2. This was proved by R.C.Thomson in 1961, in > >"Commutators in the special and general linear groups", Trans. Amer. Math. > >Soc. 101 (1961), 16-23. There are some cases however when certain > >scalar matrices are not commutators within the subgroup SL_n(K). > > Thank you for the summary; I had been under the misapprehension this > result was due to Serre. > > What is the situation for commutative rings R (with unit element)? > I was under the impression that when K-theory was translated from > topology to ring theory, the construct for the translation was the set > of groups SL_n(R), or more precisely the direct limit SL(R) of the > ordered family of them. One of the K-theoretic invariants of a ring > amounts to the difference between SL(R) and the subgroup generated by > the elementary matrices, no? (transvections, permutations, and > stretchings along one axis). Is there a K-theoretic measure of the > difference between one of these and [GL(R),GL(R)] ? Or between > the latter and the actual set of commutators? let us denote GL(R) - infinite matrices Whitehead lemma: 1) [GL(R),GL(R)]=the subgroup generated by the elementary matrices ( denoted by E(R)) 2) [E(R),E(R)]=E(R) Definition: K_1(R)=GL(R)/[GL(R),GL(R)] R- commutative SL(R)/E(R) sometimes called reduced K_1 - denoted by SK_1 Theorem: K_1(R)=R^* + SK_1(R) *** Section 2 of text below is nice, short list of such results http://www.math.uiuc.edu/K-theory/ 420: 2000 Jun 5, Algebraic K-theory of rings from a topological viewpoint, by Dominique Arlettaz. > > dave > Sent via Deja.com http://www.deja.com/