From: ksbrown@ksbrown.seanet.com (Kevin Brown) Newsgroups: sci.math Subject: Re: Number Theory Date: Wed, 19 Jun 1996 03:42:54 GMT kesslert@nevada.edu (Troy Kessler) wrote: > I know every number can be expressed as the sum of 4 squares. How > about cubes? and forth powers? and fifth powers? Is there a way to > find out how many numbers it takes as a function of the exponent? This is called Waring's Problem, because in 1770 Waring stated (without proof) that every number is expressible as a sum of 4 squares, and as a sum of 9 cubes, and as a sum of 19 fourth powers, "and so on". In 1909 Hilbert gave the first proof that for each positive integer exponent n there is an integer g(n) such that every integer is a sum of at most g(n) non-negative nth powers. An example is Lagrange's Four Square Theorem (1770), which asserts that g(2)=4. Around 1912 Wieferich and Kempner proved that g(3)=9, but it wasn't until 1964 than Chen proved g(5)=37. In the mean time, several people developed the techniques leading to the following result for all exponents greater than or equal to 6. (Square brackets signify that we are to take just the integer part of the enclosed quantity.) Let 3^n = q 2^n + r with 0 < r < 2^n. (In other words, q is the quotient of 3^n / 2^n, and r is the remainder.) If r+q <= 2^n then g(n) = 2^n + [(3/2)^n] - 2. If r+q > 2^n then / 2^n + [(3/2)^n] + [(4/3)^n] - 2 if Q = 2^n g(n) = ( \ 2^n + [(3/2)^n] + [(4/3)^n] - 3 if Q < 2^n where Q = q + (q+1)(4/3)^n. Actually, the complicated case of r+q > 2^n is somewhat academic, because it's been verified that r+q < 2^n for every n < 200000, and no value of n for which r+q exceeds 2^n is known. However, the possibility has not ben ruled out, so we have to carry along all that extra baggage. If you're only interested in exponents less than 200000 all you have to remember is g(n) = 2^n + [(3/2)^n] - 2. By the way, you may have noticed that the above results don't cover g(4). It wasn't until 1986 that Balasubramanian, Dress, and Deshouillers finally proved Waring's assertion g(4)=19 to be correct. On a closely related topic, let G(n) denote the smallest number of nth powers that can represent all but finitely many exceptions. For example, even though g(3) is 9, there are really only two numbers (23 and 239) that cannot be expressed as sums of 8 cubes. It's also known that only finitely many numbers cannot be expressed as sums of 8 cubes. Therefore, G(3) is certainly no greater than 7. It may be as low as 4, but no one knows for sure. On the other hand, we know that G(4)=16. =================================================================== MathPages at -> http://www.seanet.com/~ksbrown/ ===================================================================