From: "Robert L. Bryant" Newsgroups: sci.math.research Subject: Re: cubic surface classification Date: Wed, 19 Aug 1998 09:10:06 -0400 You wrote: >I have a question in algebraic geometry: >given q, a polynom of degree 3 over P^3 (The Projective space) , is >there a way to know whether it is reducible, based on its coefficients ? >is there something similar to quatratic polyoms classification, based on >the coefficients matrix determinants etc. ? >i.e. if q defined by a contraction of 3 vectors [x,y,z,w] with a >symetric trilinear tensor of dimension 4x4x4, what are the conditions on >a tensor defining a reducible polynom. >if anyone know a good reference to this question, based on simple >algebraic geometry, it can be very helpful Well, I was hoping that an algebraic geometer would answer this question for us, but since no one has, I'll say what I know. Maybe this will prompt a response from someone who really knows the answer. The homogeneous polynomials of degree 3 in 4 variables form a vector space of dimension 20, so the associated projective space is a P^{19}. The reducible ones are the image of the natural map B: P^3 x P^{9} --> P^{19} that is induced by the bilinear map without zero divisors C^4 x C^{10} --> C^{20} that takes a pair (l,q) consisting of a linear polynomial l and a quadratic polynomial q (each in 4 variables) and sends them to their product lq. The image B(P^3 x P^{9}) is an algebraic variety of dimension 12 and degree 220 ( = {9+3\choose3} ). Thus, by Chow's Theorem, this image is defined by the ideal I of polynomials that vanish on it. This answers your question in the affirmative, at least abstractly. Presumably, though, you will want to construct generators for this ideal and, for that, you'll need to know something about the Hilbert polynomial of the ideal I, probably. Since the image is of codimension 7 in P^{19}, the ideal I will have to have at least 7 generators. If it did have 7 generators (so that the variety is what is known as a complete intersection), then they would have to have an average degree of more than 30. (A polynomial of degree 30 in 20 variables is an awesome thing to contemplate.) Thus, it strikes me as unlikely that you really want to test cubic polynomials for factors by this method. It's instructive to consider this problem in three variables. Then the relevant mapping is B: P^2 x P^5 --> P^9, the image is of dimension 7 and degree 21 ( = {5+2\choose2} ). If this were a complete intersection, it would have to be defined by the vanishing of two polynomials, one of degree 3 and another of degree 7. (The other possibility would be one of degree 1 and the other of degree 21, but the reducible cubics clearly do not lie in any linear subspace of codimension 1.) However, it is easy to see that there is no SL(3,C)-invariant polynomial of degree 3 on S^3(C^3). Thus, the image B(P^2 x P^5) \subset P^9 cannot be a complete intersection. I have no guess about the structure of the ideal defining this image variety, but I'm sure that this is a well-studied classical subject. Can some algebraic geometer help us? Yours, Robert Bryant