From: Dave Rusin Date: Wed, 16 Dec 1998 07:38:06 -0600 (CST) To: materiaux@ecole-debroglie.fr Subject: Re: "Hessian" matrix for f : Rn -> Rp >Considering a function f : Rn -> Rp of n variables, the matrix of df >(differential of f) is the jacobian matrix. Here f takes elements of Rn(the >set of real numbers to the n) and gives vectors of Rp (not of R). > >If now f is a function from Rn to R, the Taylor-Young formula applied to f >at some point a up to the second order gives three terms : the first one is >f(a), the second one depends on the jacobian matrix of f, and the third one >depends on the hessian matrix Q of f. Q is the matrix of a quadratic form >the signature of which may give information about the extremums of f. > >My question if : what is the equivalent of this hessian matrix for f : Rn -> >Rp ? It has to be a quadratic map R^n -> R^p. You should focus on the function, not on the matrix which represents it. Indeed, the Hessian is only well- defined after bases have been picked, while the function f itself and its quadratic approximation are well-defined without reference to bases. >Copying from the case f : Rn -> R where the hessian matrix has for general >entry d2f/dx_idx_j, I suppose I have to define some object that could be >represented by a cube of components (can we call this a... tensor ?) having >d2f_k/dx_idy_j for general entry ? Yes. You need all these data to describe the quadratic approximation to f. It doesn't really matter how you arrange them. >Or do I have simply to apply the Taylor-Young formula p times, once for each >component f_k of f ? This is probably the most practical idea. >Take for example the coordinate transformation from polar to cartesian : >x = r.cos(t) >y = r.sin(t) >Here n=p=2. The Jacobian matrix is >[ [cos(t) -r.sin(t)] > [sin(t) r.cos(t)]] >What is the "hessian matrix" in this case ? You should think about the quadratic function (r,t) -> (0,0) + (r, 0) + (0, rt) if you want to approximate f near the origin, although since f has a critical point there, you don't get much information in this particular case. But again I stress it makes more sense to think about the function f and these polynomials of increasing degree which approximate it, rather than thinking about a bunch of matrices. Anyway, you will have no other choice when you start to include cubic, ... terms. This doesn't belong in sci.math.research. dave (moderator)