From: "Arthur L. Rubin" <216-5888@mcimail.com> Subject: Re: Q: help with a functional equation: Date: Thu, 25 Mar 1999 07:23:36 +0700 Newsgroups: sci.math Keywords: differential-difference equations Nils Chr. Framstad wrote: > > I would like to find the solutions to the following equation in the > unknown function f: > > f(x + q/f'(x)) - f(x) = K (q > 0 and K are arbitrary (real) constants) > > The obvious candidates of the form Ax + B and B + C log (x+D), and also > functions made from pasting such, but are there more? Preferably I'd > want every piecewise differentiable solution, but I'd be more than happy > with every strictly decreasing C1 function defined on the positive > half-line... OK, I'll try. Let g = f^-1 (the inverse function of f). Then the equation transforms to g(y+K) = g(y) + q g'(y). (If K = 0 , then g is constant, which doesn't correspond to a possible solution of the original problem.) If g is defined on a half-line (meaning, in addition to f being strictly monotone on the positive half-line, that f->+/-infinity as x goes to infinity), then we can attempt to solve this differential/difference equation. One attempt at a solution involves the possible representation of g(x) as Sum_k P_k(y) exp(lambda_k y), where the P_k are polynomials, (or, when necessary, polynomials in y and log(y), etc.), and the lambda_k are a decreasing (increasing if f was decreasing) (in real part) sequence of complex numbers. Solving for possible values of lambda, we find that the "inditial" equation is exp(K lambda) = 1 + q lambda. The real solutions of this are 0 and a unique lambda_0 (which is non-zero unless K=q). Hence the only solutions with real lambda are of the form g(y) = A + B exp(lambda_0 y), or A + B y (if q = K), which correspond to the solutions you gave. However, there are other complex solutions of the inditial equation for lambda; if Re(lambda') < lambda_0, you can construct monotone solutions as y -> +infinity of the form g(y) = A + B exp(lambda_0 y) + Re(C exp(lambda' y)); while if Re(lambda') > lambda_0, you can construct monotone solutions of the same form as y->-infinity. I don't remember where the solutions of the inditial equations actually reside in the complex plane, so I can't tell you what form additional solutions would have, but they do exist if K>0. It appears that there are no solutions for K<=0, as the inditial equation has only 0 for a real root, corresponding to all solutions defined on an infinite interval being non-monotone somewhere on that interval. If g is real-analytic with radius of convergence >|K| somewhere, we get the same result by equating coefficients of the power series. We do need to show that f(x) cannot go to a finite limit as x -> +infinity, but I'll leave that as an exercise to the reader. > > I will probably face similar equations later, so a textbook reference > would be appreciated as well. I have a text on differential/difference equations somewhere...but I can't find it. I find the series and asymtotic methods described in _Differential Equations_, Harry Hockstadt (New York: Holt Rinehart Winston, 1963-1964) helpfull. -- Arthur L. Rubin 216-5888@mcimail.com